Clevider wrote:
Menghini wrote:
I believe the rule is, you have to have a 3 of a kind, after that you get 1 VP extra per same number die. When you roll 3x 3 and 3x 2, I guess you want to count the highest, which is 3x 3 (3 VPs).
Is this a belief based on evidence? I skimmed my 1st Edition rule book and didn't find anything supporting one interpretation over the other. As far as I can tell, it comes down to a house rule at this point.
With all due respect to all who have responded so far, I can't think of any reason to interpret it any other way than, yes, you count all the VP's.
In other words, if you roll six 3's, that's 3 + 1 + 1 + 1 = 6.
If you roll three 3's and three 2's, that's 3 + 2 = 5.
My reasoning? Say your final roll is three 2's, two Energy, one Attack.
I think we'd all agree that that results in scoring 2 VP's, taking 2 Energy cubes, and making 1 Attack. All the dice that can be used are used.
So if you roll two sets of triplets, why wouldn't you score VP's for the first set and VP's for the second one?
Again, no offense to the prior comments (I fear my written tone seems harsh, but that doesn't correctly convey how I feel; maybe an emoticon will help: :meeple: ), but this seems straightforward to me.